7k^2+46k+24=0

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Solution for 7k^2+46k+24=0 equation: 



7k^2+46k+24=0

a = 7; b = 46; c = +24;
Δ = b2-4ac
Δ = 462-4·7·24
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-38}{2*7}=\frac{-84}{14}
=-6
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+38}{2*7}=\frac{-8}{14}
=-4/7
$

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